Q:

What is the solution of the system? Use the elimination method. {4x+2y=182x+3y=15 Enter your answer in the boxes.

Accepted Solution

A:
[tex] \left \{ {{4x+2y=18(1)} \atop {2x+3y=15(2)}} \right. [/tex]
Lets multiply equation (2) by -2 to get:
[tex]-4x-6y=-30[/tex]

Now we can add equations (1) and (2) to eliminate x:
[tex] \left \{ {{4x+2y=18}+ \atop {-4x-6y=-30}} \right. [/tex]
[tex]-4y=-12[/tex]
[tex]y= \frac{-12}{-4} [/tex]
[tex]y=3[/tex]
Now that we know the value of y, we can replace it in equation (1) to get the value of x:
[tex]4x+2(3)=18[/tex]
[tex]4x+6=18[/tex]
[tex]4x=12[/tex]
[tex]x= \frac{12}{3} [/tex]
[tex]x=3[/tex]

We can conclude that both x and y are equal to 3.