Q:

A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $3,000 or $6,000. If the partnership raised $258,000, then how many investors contributed $3,000 and how many contributed $6,000?x = $3,000 investorsy = $6,000 investorsFormulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- and y-variables. Solve the system by the elimination method. Be sure to state your final answer in terms of the original question.A jar contains 70 nickels and dimes worth $5.70. How many of each kind of coin are in the jar?Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- and y-variables. Solve the system by the elimination method. Be sure to state your final answer in terms of the original question.The concession stand at an ice hockey rink had receipts of $7400 from selling a total of 3000 sodas and hot dogs. If each soda sold for $2 and each hot dog sold for $3, how many of each were sold?x= soday= hotdogs

Accepted Solution

A:
Answer:There are 26 investors which contributed 6,000And 34 investors which contributed 3,000Step-by-step explanation:You need to set up a two equation problem[tex]\left \{ {{258,000=6,000y+3,000x} \atop {60=y+x}} \right.[/tex]Now you have to clear "x" or "y" from the second equation:[tex]y = 60 - x[/tex]And replace on the first equation:[tex]258,000 = 6,000 (60 - x) + 3,000x\\258,000 = 360,000 - 6,000x + 3,000x\\3,000x = 360,000 - 258,000\\x = 102,000/3,000\\x = 34[/tex]And now you use this "x" vale on the second equation[tex]60 = y + x\\60 = y + 34\\60 - 34 = y\\y = 26[/tex]There are 26 investors which contributed 6,000And 34 investors which contributed 3,000