MATH SOLVE

3 months ago

Q:
# Starting at sea level, a submarine descended at a constant rate to a depth of β4/5 mile relative to sea level in 3 minutes. What was the submarine's depth relative to sea level after the first minute? Enter your answer as a fraction, in simplest form, in the box.

Accepted Solution

A:

Answer:[tex]\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles[/tex]Step-by-step explanation:Starting at sea level, a submarine descended at a constant rate to a depth of β4/5 mile relative to sea level in 3 minutes. Total time = 3 minutes[tex]\texttt{Total depth descended in 3 minutes =}-\frac{4}{5}miles[/tex]We need to find what was the submarine's depth relative to sea level after the first minute,[tex]\texttt{Depth descended in per minute =}\frac{-\frac{4}{5}}{3}=-\frac{4}{15}miles[/tex][tex]\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}\times 1=-\frac{4}{15}miles\\\\\texttt{Submarine's depth relative to sea level after the first minute =}-\frac{4}{15}miles[/tex]