A rectangular dartboard has an area of 648 square centimeters. The triangular part of the dartboard has an area of 162 square centimeters. A dart is randomly thrown at the dartboard.Assuming the dart lands in the rectangle, what is the probability that it lands inside the triangle?

Answer:The probability that the dart lands inside the triangle is 0.25Step-by-step explanation:* Lets explain how to find the probability of an event - The probability of an Event = Number of favorable outcomes ÷ Total   number of possible outcomes- P(A) = n(E) ÷ n(S) , where# P(A) means finding the probability of an event A # n(E) means the number of favorable outcomes of an event# n(S) means set of all possible outcomes of an event- P(A) < 1 * Lets solve the problem- A rectangular dartboard has an area of 648 cm²- The triangular part of the dartboard has an area of 162 cm²- A dart is randomly thrown at the dartboard- The dart lands in the rectangle∴ The area of the rectangle is the set of all possible outcomes n(S)- The probability P(A) that the dart lands inside the triangle∴ The area of the triangle is set of favorable outcomes of an    event n(E)∵ P(A) = n(E) ÷ n(S)∴ P(T) = area of the triangle ÷ area of the rectangle∵ Area of the rectangle is 648 cm²∴ n(S) = 648∵ The area of the triangle is 162 cm²∴ n(E) = 162∴ P(T) = 162 ÷ 648 = 1/4 = 0.25 * The probability that the dart lands inside the triangle is 0.25